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type	Item https://schema.org/Answer
described by	https://stackoverflow.com/q/38987
md:url	https://stackoverflow.com/a/44512 https://stackoverflow.com/a/38989
md:author	http://dev.restore.ovi.cnr.it:8890/about/id/entity/https/stackoverflow.com/q/38987#id0x7fe83035bd18 http://dev.restore.ovi.cnr.it:8890/about/id/entity/https/stackoverflow.com/q/38987#id0x7fe83035ba28
md:dateCreated	2008-09-02 07:49:27Z 2008-09-04 19:08:25Z
md:upvoteCount	158 101
md:commentCount	2 1
md:text	I wanted something similar, but with the ability to specify how the values on duplicate keys were merged, so I hacked this out (but did not heavily test it). Obviously this is not a single expression, but it is a single function call. def merge(d1, d2, merge_fn=lambda x,y:y): """ Merges two dictionaries, non-destructively, combining values on duplicate keys as defined by the optional merge function. The default behavior replaces the values in d1 with corresponding values in d2. (There is no other generally applicable merge strategy, but often you'll have homogeneous types in your dicts, so specifying a merge technique can be valuable.) Examples: >>> d1 {'a': 1, 'c': 3, 'b': 2} >>> merge(d1, d1) {'a': 1, 'c': 3, 'b': 2} >>> merge(d1, d1, lambda x,y: x+y) {'a': 2, 'c': 6, 'b': 4} """ result = dict(d1) for k,v in d2.iteritems(): if k in result: result[k] = merge_fn(result[k], v) else: result[k] = v return result x = {'a':1, 'b': 2} y = {'b':10, 'c': 11} z = dict(x.items() + y.items()) print z For items with keys in both dictionaries ('b'), you can control which one ends up in the output by putting that one last. UPDATE For Python 3.x use `dict(list(x.items()) + list(y.items()))`
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